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Ufumbuzi - Tiger algebra Suluhishaji

264548.77

264548.77

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (5486, 15, 12, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 486$ , $r = 15 %$ , $n = 12$ , $t = 26$ .

$c i (5486, 15, 12, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 486$ , $r = 15 %$ , $n = 12$ , $t = 26$ .

$P = 5486, r = 15 %, n = 12, t = 26$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 486$ , $r = 15 %$ , $n = 12$ , $t = 26$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 486$ , $r = 15 %$ , $n = 12$ , $t = 26$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 486$ , $r = 15 %$ , $n = 12$ , $t = 26$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 312$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 312, {(1 + r / n)}^{(n t)} = 48.2225251931$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{312} = 48.2225251931$

$r / n = 0.0125, n t = 312, {(1 + r / n)}^{(n t)} = 48.2225251931$ .

$48.2225251931$

$r / n = 0.0125, n t = 312, {(1 + r / n)}^{(n t)} = 48.2225251931$ .

3. Hesabu kiasi cha mwisho

$A = 264548.77$

$264548.77$

$5, 486 \cdot 48.2225251931 = 264548.77$ .

$264548.77$

$5, 486 \cdot 48.2225251931 = 264548.77$ .

$264548.77$

$5, 486 \cdot 48.2225251931 = 264548.77$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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