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Ufumbuzi - Tiger algebra Suluhishaji

17509.07

17509.07

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (5429, 5, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 429$ , $r = 5 %$ , $n = 1$ , $t = 24$ .

$c i (5429, 5, 1, 24)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 429$ , $r = 5 %$ , $n = 1$ , $t = 24$ .

$P = 5429, r = 5 %, n = 1, t = 24$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 429$ , $r = 5 %$ , $n = 1$ , $t = 24$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 429$ , $r = 5 %$ , $n = 1$ , $t = 24$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 429$ , $r = 5 %$ , $n = 1$ , $t = 24$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.05$

$n t = 24$

${(1 + r / n)}^{(n t)}$

$r / n = 0.05, n t = 24, {(1 + r / n)}^{(n t)} = 3.2250999437$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.05)}^{24} = 3.2250999437$

$r / n = 0.05, n t = 24, {(1 + r / n)}^{(n t)} = 3.2250999437$ .

$3.2250999437$

$r / n = 0.05, n t = 24, {(1 + r / n)}^{(n t)} = 3.2250999437$ .

3. Hesabu kiasi cha mwisho

$A = 17509.07$

$17509.07$

$5, 429 \cdot 3.2250999437 = 17509.07$ .

$17509.07$

$5, 429 \cdot 3.2250999437 = 17509.07$ .

$17509.07$

$5, 429 \cdot 3.2250999437 = 17509.07$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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