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Ufumbuzi - Tiger algebra Suluhishaji

107593.79

107593.79

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (5217, 11, 1, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 217$ , $r = 11 %$ , $n = 1$ , $t = 29$ .

$c i (5217, 11, 1, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 217$ , $r = 11 %$ , $n = 1$ , $t = 29$ .

$P = 5217, r = 11 %, n = 1, t = 29$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 217$ , $r = 11 %$ , $n = 1$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 217$ , $r = 11 %$ , $n = 1$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 5, 217$ , $r = 11 %$ , $n = 1$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.11$

$n t = 29$

${(1 + r / n)}^{(n t)}$

$r / n = 0.11, n t = 29, {(1 + r / n)}^{(n t)} = 20.6236906053$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.11)}^{29} = 20.6236906053$

$r / n = 0.11, n t = 29, {(1 + r / n)}^{(n t)} = 20.6236906053$ .

$20.6236906053$

$r / n = 0.11, n t = 29, {(1 + r / n)}^{(n t)} = 20.6236906053$ .

3. Hesabu kiasi cha mwisho

$A = 107593.79$

$107593.79$

$5, 217 \cdot 20.6236906053 = 107593.79$ .

$107593.79$

$5, 217 \cdot 20.6236906053 = 107593.79$ .

$107593.79$

$5, 217 \cdot 20.6236906053 = 107593.79$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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