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Ufumbuzi - Tiger algebra Suluhishaji

8390.41

8390.41

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (4912, 11, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 912$ , $r = 11 %$ , $n = 2$ , $t = 5$ .

$c i (4912, 11, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 912$ , $r = 11 %$ , $n = 2$ , $t = 5$ .

$P = 4912, r = 11 %, n = 2, t = 5$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 912$ , $r = 11 %$ , $n = 2$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 912$ , $r = 11 %$ , $n = 2$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 912$ , $r = 11 %$ , $n = 2$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.055$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.055, n t = 10, {(1 + r / n)}^{(n t)} = 1.7081444584$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.055)}^{10} = 1.7081444584$

$r / n = 0.055, n t = 10, {(1 + r / n)}^{(n t)} = 1.7081444584$ .

$1.7081444584$

$r / n = 0.055, n t = 10, {(1 + r / n)}^{(n t)} = 1.7081444584$ .

3. Hesabu kiasi cha mwisho

$A = 8390.41$

$8390.41$

$4, 912 \cdot 1.7081444584 = 8390.41$ .

$8390.41$

$4, 912 \cdot 1.7081444584 = 8390.41$ .

$8390.41$

$4, 912 \cdot 1.7081444584 = 8390.41$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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