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Ufumbuzi - Tiger algebra Suluhishaji

29048.24

29048.24

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (4834, 9, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 834$ , $r = 9 %$ , $n = 12$ , $t = 20$ .

$c i (4834, 9, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 834$ , $r = 9 %$ , $n = 12$ , $t = 20$ .

$P = 4834, r = 9 %, n = 12, t = 20$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 834$ , $r = 9 %$ , $n = 12$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 834$ , $r = 9 %$ , $n = 12$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 834$ , $r = 9 %$ , $n = 12$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0075$

$n t = 240$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0075, n t = 240, {(1 + r / n)}^{(n t)} = 6.0091515245$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0075)}^{240} = 6.0091515245$

$r / n = 0.0075, n t = 240, {(1 + r / n)}^{(n t)} = 6.0091515245$ .

$6.0091515245$

$r / n = 0.0075, n t = 240, {(1 + r / n)}^{(n t)} = 6.0091515245$ .

3. Hesabu kiasi cha mwisho

$A = 29048.24$

$29048.24$

$4, 834 \cdot 6.0091515245 = 29048.24$ .

$29048.24$

$4, 834 \cdot 6.0091515245 = 29048.24$ .

$29048.24$

$4, 834 \cdot 6.0091515245 = 29048.24$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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