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Ufumbuzi - Tiger algebra Suluhishaji

25340.11

25340.11

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (4727, 10, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 727$ , $r = 10 %$ , $n = 4$ , $t = 17$ .

$c i (4727, 10, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 727$ , $r = 10 %$ , $n = 4$ , $t = 17$ .

$P = 4727, r = 10 %, n = 4, t = 17$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 727$ , $r = 10 %$ , $n = 4$ , $t = 17$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 727$ , $r = 10 %$ , $n = 4$ , $t = 17$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 727$ , $r = 10 %$ , $n = 4$ , $t = 17$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.025$

$n t = 68$

${(1 + r / n)}^{(n t)}$

$r / n = 0.025, n t = 68, {(1 + r / n)}^{(n t)} = 5.3607165784$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.025)}^{68} = 5.3607165784$

$r / n = 0.025, n t = 68, {(1 + r / n)}^{(n t)} = 5.3607165784$ .

$5.3607165784$

$r / n = 0.025, n t = 68, {(1 + r / n)}^{(n t)} = 5.3607165784$ .

3. Hesabu kiasi cha mwisho

$A = 25340.11$

$25340.11$

$4, 727 \cdot 5.3607165784 = 25340.11$ .

$25340.11$

$4, 727 \cdot 5.3607165784 = 25340.11$ .

$25340.11$

$4, 727 \cdot 5.3607165784 = 25340.11$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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