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Ufumbuzi - Tiger algebra Suluhishaji

12693.67

12693.67

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (4471, 5, 4, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 471$ , $r = 5 %$ , $n = 4$ , $t = 21$ .

$c i (4471, 5, 4, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 471$ , $r = 5 %$ , $n = 4$ , $t = 21$ .

$P = 4471, r = 5 %, n = 4, t = 21$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 471$ , $r = 5 %$ , $n = 4$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 471$ , $r = 5 %$ , $n = 4$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 471$ , $r = 5 %$ , $n = 4$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 84$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 84, {(1 + r / n)}^{(n t)} = 2.8391130012$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{84} = 2.8391130012$

$r / n = 0.0125, n t = 84, {(1 + r / n)}^{(n t)} = 2.8391130012$ .

$2.8391130012$

$r / n = 0.0125, n t = 84, {(1 + r / n)}^{(n t)} = 2.8391130012$ .

3. Hesabu kiasi cha mwisho

$A = 12693.67$

$12693.67$

$4, 471 \cdot 2.8391130012 = 12693.67$ .

$12693.67$

$4, 471 \cdot 2.8391130012 = 12693.67$ .

$12693.67$

$4, 471 \cdot 2.8391130012 = 12693.67$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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