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Ufumbuzi - Tiger algebra Suluhishaji

196336.88

196336.88

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (4393, 14, 1, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 393$ , $r = 14 %$ , $n = 1$ , $t = 29$ .

$c i (4393, 14, 1, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 393$ , $r = 14 %$ , $n = 1$ , $t = 29$ .

$P = 4393, r = 14 %, n = 1, t = 29$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 393$ , $r = 14 %$ , $n = 1$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 393$ , $r = 14 %$ , $n = 1$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 4, 393$ , $r = 14 %$ , $n = 1$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 29$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 29, {(1 + r / n)}^{(n t)} = 44.6931215643$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{29} = 44.6931215643$

$r / n = 0.14, n t = 29, {(1 + r / n)}^{(n t)} = 44.6931215643$ .

$44.6931215643$

$r / n = 0.14, n t = 29, {(1 + r / n)}^{(n t)} = 44.6931215643$ .

3. Hesabu kiasi cha mwisho

$A = 196336.88$

$196336.88$

$4, 393 \cdot 44.6931215643 = 196336.88$ .

$196336.88$

$4, 393 \cdot 44.6931215643 = 196336.88$ .

$196336.88$

$4, 393 \cdot 44.6931215643 = 196336.88$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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