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Ufumbuzi - Tiger algebra Suluhishaji

34935.91

34935.91

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3910, 11, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 910$ , $r = 11 %$ , $n = 12$ , $t = 20$ .

$c i (3910, 11, 12, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 910$ , $r = 11 %$ , $n = 12$ , $t = 20$ .

$P = 3910, r = 11 %, n = 12, t = 20$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 910$ , $r = 11 %$ , $n = 12$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 910$ , $r = 11 %$ , $n = 12$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 910$ , $r = 11 %$ , $n = 12$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0091666667$

$n t = 240$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0091666667, n t = 240, {(1 + r / n)}^{(n t)} = 8.9350153492$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0091666667)}^{240} = 8.9350153492$

$r / n = 0.0091666667, n t = 240, {(1 + r / n)}^{(n t)} = 8.9350153492$ .

$8.9350153492$

$r / n = 0.0091666667, n t = 240, {(1 + r / n)}^{(n t)} = 8.9350153492$ .

3. Hesabu kiasi cha mwisho

$A = 34935.91$

$34935.91$

$3, 910 \cdot 8.9350153492 = 34935.91$ .

$34935.91$

$3, 910 \cdot 8.9350153492 = 34935.91$ .

$34935.91$

$3, 910 \cdot 8.9350153492 = 34935.91$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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