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Ufumbuzi - Tiger algebra Suluhishaji

13439.69

13439.69

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3893, 10, 1, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 893$ , $r = 10 %$ , $n = 1$ , $t = 13$ .

$c i (3893, 10, 1, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 893$ , $r = 10 %$ , $n = 1$ , $t = 13$ .

$P = 3893, r = 10 %, n = 1, t = 13$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 893$ , $r = 10 %$ , $n = 1$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 893$ , $r = 10 %$ , $n = 1$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 893$ , $r = 10 %$ , $n = 1$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.1$

$n t = 13$

${(1 + r / n)}^{(n t)}$

$r / n = 0.1, n t = 13, {(1 + r / n)}^{(n t)} = 3.4522712144$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.1)}^{13} = 3.4522712144$

$r / n = 0.1, n t = 13, {(1 + r / n)}^{(n t)} = 3.4522712144$ .

$3.4522712144$

$r / n = 0.1, n t = 13, {(1 + r / n)}^{(n t)} = 3.4522712144$ .

3. Hesabu kiasi cha mwisho

$A = 13439.69$

$13439.69$

$3, 893 \cdot 3.4522712144 = 13439.69$ .

$13439.69$

$3, 893 \cdot 3.4522712144 = 13439.69$ .

$13439.69$

$3, 893 \cdot 3.4522712144 = 13439.69$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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