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Ufumbuzi - Tiger algebra Suluhishaji

22078.92

22078.92

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3796, 9, 2, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 796$ , $r = 9 %$ , $n = 2$ , $t = 20$ .

$c i (3796, 9, 2, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 796$ , $r = 9 %$ , $n = 2$ , $t = 20$ .

$P = 3796, r = 9 %, n = 2, t = 20$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 796$ , $r = 9 %$ , $n = 2$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 796$ , $r = 9 %$ , $n = 2$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 796$ , $r = 9 %$ , $n = 2$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.045$

$n t = 40$

${(1 + r / n)}^{(n t)}$

$r / n = 0.045, n t = 40, {(1 + r / n)}^{(n t)} = 5.8163645376$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.045)}^{40} = 5.8163645376$

$r / n = 0.045, n t = 40, {(1 + r / n)}^{(n t)} = 5.8163645376$ .

$5.8163645376$

$r / n = 0.045, n t = 40, {(1 + r / n)}^{(n t)} = 5.8163645376$ .

3. Hesabu kiasi cha mwisho

$A = 22078.92$

$22078.92$

$3, 796 \cdot 5.8163645376 = 22078.92$ .

$22078.92$

$3, 796 \cdot 5.8163645376 = 22078.92$ .

$22078.92$

$3, 796 \cdot 5.8163645376 = 22078.92$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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