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Ufumbuzi - Tiger algebra Suluhishaji

64599.56

64599.56

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3768, 14, 2, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 768$ , $r = 14 %$ , $n = 2$ , $t = 21$ .

$c i (3768, 14, 2, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 768$ , $r = 14 %$ , $n = 2$ , $t = 21$ .

$P = 3768, r = 14 %, n = 2, t = 21$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 768$ , $r = 14 %$ , $n = 2$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 768$ , $r = 14 %$ , $n = 2$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 768$ , $r = 14 %$ , $n = 2$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 42$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 42, {(1 + r / n)}^{(n t)} = 17.1442567801$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{42} = 17.1442567801$

$r / n = 0.07, n t = 42, {(1 + r / n)}^{(n t)} = 17.1442567801$ .

$17.1442567801$

$r / n = 0.07, n t = 42, {(1 + r / n)}^{(n t)} = 17.1442567801$ .

3. Hesabu kiasi cha mwisho

$A = 64599.56$

$64599.56$

$3, 768 \cdot 17.1442567801 = 64599.56$ .

$64599.56$

$3, 768 \cdot 17.1442567801 = 64599.56$ .

$64599.56$

$3, 768 \cdot 17.1442567801 = 64599.56$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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