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Ufumbuzi - Tiger algebra Suluhishaji

124525.85

124525.85

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3621, 14, 1, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 621$ , $r = 14 %$ , $n = 1$ , $t = 27$ .

$c i (3621, 14, 1, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 621$ , $r = 14 %$ , $n = 1$ , $t = 27$ .

$P = 3621, r = 14 %, n = 1, t = 27$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 621$ , $r = 14 %$ , $n = 1$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 621$ , $r = 14 %$ , $n = 1$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 621$ , $r = 14 %$ , $n = 1$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.14$

$n t = 27$

${(1 + r / n)}^{(n t)}$

$r / n = 0.14, n t = 27, {(1 + r / n)}^{(n t)} = 34.3899057897$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.14)}^{27} = 34.3899057897$

$r / n = 0.14, n t = 27, {(1 + r / n)}^{(n t)} = 34.3899057897$ .

$34.3899057897$

$r / n = 0.14, n t = 27, {(1 + r / n)}^{(n t)} = 34.3899057897$ .

3. Hesabu kiasi cha mwisho

$A = 124525.85$

$124525.85$

$3, 621 \cdot 34.3899057897 = 124525.85$ .

$124525.85$

$3, 621 \cdot 34.3899057897 = 124525.85$ .

$124525.85$

$3, 621 \cdot 34.3899057897 = 124525.85$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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