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Ufumbuzi - Tiger algebra Suluhishaji

24876.99

24876.99

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3520, 13, 1, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 520$ , $r = 13 %$ , $n = 1$ , $t = 16$ .

$c i (3520, 13, 1, 16)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 520$ , $r = 13 %$ , $n = 1$ , $t = 16$ .

$P = 3520, r = 13 %, n = 1, t = 16$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 520$ , $r = 13 %$ , $n = 1$ , $t = 16$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 520$ , $r = 13 %$ , $n = 1$ , $t = 16$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 520$ , $r = 13 %$ , $n = 1$ , $t = 16$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.13$

$n t = 16$

${(1 + r / n)}^{(n t)}$

$r / n = 0.13, n t = 16, {(1 + r / n)}^{(n t)} = 7.0673255268$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.13)}^{16} = 7.0673255268$

$r / n = 0.13, n t = 16, {(1 + r / n)}^{(n t)} = 7.0673255268$ .

$7.0673255268$

$r / n = 0.13, n t = 16, {(1 + r / n)}^{(n t)} = 7.0673255268$ .

3. Hesabu kiasi cha mwisho

$A = 24876.99$

$24876.99$

$3, 520 \cdot 7.0673255268 = 24876.99$ .

$24876.99$

$3, 520 \cdot 7.0673255268 = 24876.99$ .

$24876.99$

$3, 520 \cdot 7.0673255268 = 24876.99$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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