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Ufumbuzi - Tiger algebra Suluhishaji

11668.25

11668.25

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3238, 12, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 238$ , $r = 12 %$ , $n = 2$ , $t = 11$ .

$c i (3238, 12, 2, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 238$ , $r = 12 %$ , $n = 2$ , $t = 11$ .

$P = 3238, r = 12 %, n = 2, t = 11$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 238$ , $r = 12 %$ , $n = 2$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 238$ , $r = 12 %$ , $n = 2$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 238$ , $r = 12 %$ , $n = 2$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 22$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 22, {(1 + r / n)}^{(n t)} = 3.6035374166$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{22} = 3.6035374166$

$r / n = 0.06, n t = 22, {(1 + r / n)}^{(n t)} = 3.6035374166$ .

$3.6035374166$

$r / n = 0.06, n t = 22, {(1 + r / n)}^{(n t)} = 3.6035374166$ .

3. Hesabu kiasi cha mwisho

$A = 11668.25$

$11668.25$

$3, 238 \cdot 3.6035374166 = 11668.25$ .

$11668.25$

$3, 238 \cdot 3.6035374166 = 11668.25$ .

$11668.25$

$3, 238 \cdot 3.6035374166 = 11668.25$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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