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Ufumbuzi - Tiger algebra Suluhishaji

3120.98

3120.98

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (3090, 1, 2, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 090$ , $r = 1 %$ , $n = 2$ , $t = 1$ .

$c i (3090, 1, 2, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 090$ , $r = 1 %$ , $n = 2$ , $t = 1$ .

$P = 3090, r = 1 %, n = 2, t = 1$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 090$ , $r = 1 %$ , $n = 2$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 090$ , $r = 1 %$ , $n = 2$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 3, 090$ , $r = 1 %$ , $n = 2$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 2$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 2, {(1 + r / n)}^{(n t)} = 1.010025$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{2} = 1.010025$

$r / n = 0.005, n t = 2, {(1 + r / n)}^{(n t)} = 1.010025$ .

$1.010025$

$r / n = 0.005, n t = 2, {(1 + r / n)}^{(n t)} = 1.010025$ .

3. Hesabu kiasi cha mwisho

$A = 3120.98$

$3120.98$

$3, 090 \cdot 1.010025 = 3120.98$ .

$3120.98$

$3, 090 \cdot 1.010025 = 3120.98$ .

$3120.98$

$3, 090 \cdot 1.010025 = 3120.98$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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