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Ufumbuzi - Tiger algebra Suluhishaji

16910.31

16910.31

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2981, 6, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 981$ , $r = 6 %$ , $n = 12$ , $t = 29$ .

$c i (2981, 6, 12, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 981$ , $r = 6 %$ , $n = 12$ , $t = 29$ .

$P = 2981, r = 6 %, n = 12, t = 29$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 981$ , $r = 6 %$ , $n = 12$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 981$ , $r = 6 %$ , $n = 12$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 981$ , $r = 6 %$ , $n = 12$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 348$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 348, {(1 + r / n)}^{(n t)} = 5.672695751$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{348} = 5.672695751$

$r / n = 0.005, n t = 348, {(1 + r / n)}^{(n t)} = 5.672695751$ .

$5.672695751$

$r / n = 0.005, n t = 348, {(1 + r / n)}^{(n t)} = 5.672695751$ .

3. Hesabu kiasi cha mwisho

$A = 16910.31$

$16910.31$

$2, 981 \cdot 5.672695751 = 16910.31$ .

$16910.31$

$2, 981 \cdot 5.672695751 = 16910.31$ .

$16910.31$

$2, 981 \cdot 5.672695751 = 16910.31$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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