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Ufumbuzi - Tiger algebra Suluhishaji

11618.21

11618.21

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2953, 6, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 953$ , $r = 6 %$ , $n = 4$ , $t = 23$ .

$c i (2953, 6, 4, 23)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 953$ , $r = 6 %$ , $n = 4$ , $t = 23$ .

$P = 2953, r = 6 %, n = 4, t = 23$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 953$ , $r = 6 %$ , $n = 4$ , $t = 23$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 953$ , $r = 6 %$ , $n = 4$ , $t = 23$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 953$ , $r = 6 %$ , $n = 4$ , $t = 23$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.015$

$n t = 92$

${(1 + r / n)}^{(n t)}$

$r / n = 0.015, n t = 92, {(1 + r / n)}^{(n t)} = 3.9343762243$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.015)}^{92} = 3.9343762243$

$r / n = 0.015, n t = 92, {(1 + r / n)}^{(n t)} = 3.9343762243$ .

$3.9343762243$

$r / n = 0.015, n t = 92, {(1 + r / n)}^{(n t)} = 3.9343762243$ .

3. Hesabu kiasi cha mwisho

$A = 11618.21$

$11618.21$

$2, 953 \cdot 3.9343762243 = 11618.21$ .

$11618.21$

$2, 953 \cdot 3.9343762243 = 11618.21$ .

$11618.21$

$2, 953 \cdot 3.9343762243 = 11618.21$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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