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Ufumbuzi - Tiger algebra Suluhishaji

4341.36

4341.36

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2913, 2, 4, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 913$ , $r = 2 %$ , $n = 4$ , $t = 20$ .

$c i (2913, 2, 4, 20)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 913$ , $r = 2 %$ , $n = 4$ , $t = 20$ .

$P = 2913, r = 2 %, n = 4, t = 20$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 913$ , $r = 2 %$ , $n = 4$ , $t = 20$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 913$ , $r = 2 %$ , $n = 4$ , $t = 20$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 913$ , $r = 2 %$ , $n = 4$ , $t = 20$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 80$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 80, {(1 + r / n)}^{(n t)} = 1.4903385678$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{80} = 1.4903385678$

$r / n = 0.005, n t = 80, {(1 + r / n)}^{(n t)} = 1.4903385678$ .

$1.4903385678$

$r / n = 0.005, n t = 80, {(1 + r / n)}^{(n t)} = 1.4903385678$ .

3. Hesabu kiasi cha mwisho

$A = 4341.36$

$4341.36$

$2, 913 \cdot 1.4903385678 = 4341.36$ .

$4341.36$

$2, 913 \cdot 1.4903385678 = 4341.36$ .

$4341.36$

$2, 913 \cdot 1.4903385678 = 4341.36$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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