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Ufumbuzi - Tiger algebra Suluhishaji

14740.43

14740.43

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2860, 15, 12, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 860$ , $r = 15 %$ , $n = 12$ , $t = 11$ .

$c i (2860, 15, 12, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 860$ , $r = 15 %$ , $n = 12$ , $t = 11$ .

$P = 2860, r = 15 %, n = 12, t = 11$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 860$ , $r = 15 %$ , $n = 12$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 860$ , $r = 15 %$ , $n = 12$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 860$ , $r = 15 %$ , $n = 12$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 132$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 132, {(1 + r / n)}^{(n t)} = 5.1539975651$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{132} = 5.1539975651$

$r / n = 0.0125, n t = 132, {(1 + r / n)}^{(n t)} = 5.1539975651$ .

$5.1539975651$

$r / n = 0.0125, n t = 132, {(1 + r / n)}^{(n t)} = 5.1539975651$ .

3. Hesabu kiasi cha mwisho

$A = 14740.43$

$14740.43$

$2, 860 \cdot 5.1539975651 = 14740.43$ .

$14740.43$

$2, 860 \cdot 5.1539975651 = 14740.43$ .

$14740.43$

$2, 860 \cdot 5.1539975651 = 14740.43$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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