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Ufumbuzi - Tiger algebra Suluhishaji

6299.34

6299.34

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2838, 8, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 838$ , $r = 8 %$ , $n = 12$ , $t = 10$ .

$c i (2838, 8, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 838$ , $r = 8 %$ , $n = 12$ , $t = 10$ .

$P = 2838, r = 8 %, n = 12, t = 10$

$\frac{8}{100} = 0.08$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 838$ , $r = 8 %$ , $n = 12$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 838$ , $r = 8 %$ , $n = 12$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 838$ , $r = 8 %$ , $n = 12$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0066666667$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0066666667, n t = 120, {(1 + r / n)}^{(n t)} = 2.2196402345$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0066666667)}^{120} = 2.2196402345$

$r / n = 0.0066666667, n t = 120, {(1 + r / n)}^{(n t)} = 2.2196402345$ .

$2.2196402345$

$r / n = 0.0066666667, n t = 120, {(1 + r / n)}^{(n t)} = 2.2196402345$ .

3. Hesabu kiasi cha mwisho

$A = 6299.34$

$6299.34$

$2, 838 \cdot 2.2196402345 = 6299.34$ .

$6299.34$

$2, 838 \cdot 2.2196402345 = 6299.34$ .

$6299.34$

$2, 838 \cdot 2.2196402345 = 6299.34$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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