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Ufumbuzi - Tiger algebra Suluhishaji

18689.88

18689.88

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2811, 14, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 811$ , $r = 14 %$ , $n = 2$ , $t = 14$ .

$c i (2811, 14, 2, 14)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 811$ , $r = 14 %$ , $n = 2$ , $t = 14$ .

$P = 2811, r = 14 %, n = 2, t = 14$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 811$ , $r = 14 %$ , $n = 2$ , $t = 14$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 811$ , $r = 14 %$ , $n = 2$ , $t = 14$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 811$ , $r = 14 %$ , $n = 2$ , $t = 14$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 28, {(1 + r / n)}^{(n t)} = 6.6488383638$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{28} = 6.6488383638$

$r / n = 0.07, n t = 28, {(1 + r / n)}^{(n t)} = 6.6488383638$ .

$6.6488383638$

$r / n = 0.07, n t = 28, {(1 + r / n)}^{(n t)} = 6.6488383638$ .

3. Hesabu kiasi cha mwisho

$A = 18689.88$

$18689.88$

$2, 811 \cdot 6.6488383638 = 18689.88$ .

$18689.88$

$2, 811 \cdot 6.6488383638 = 18689.88$ .

$18689.88$

$2, 811 \cdot 6.6488383638 = 18689.88$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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