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Ufumbuzi - Tiger algebra Suluhishaji

3570.79

3570.79

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2657, 6, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 657$ , $r = 6 %$ , $n = 2$ , $t = 5$ .

$c i (2657, 6, 2, 5)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 657$ , $r = 6 %$ , $n = 2$ , $t = 5$ .

$P = 2657, r = 6 %, n = 2, t = 5$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 657$ , $r = 6 %$ , $n = 2$ , $t = 5$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 657$ , $r = 6 %$ , $n = 2$ , $t = 5$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 657$ , $r = 6 %$ , $n = 2$ , $t = 5$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 10$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 10, {(1 + r / n)}^{(n t)} = 1.3439163793$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{10} = 1.3439163793$

$r / n = 0.03, n t = 10, {(1 + r / n)}^{(n t)} = 1.3439163793$ .

$1.3439163793$

$r / n = 0.03, n t = 10, {(1 + r / n)}^{(n t)} = 1.3439163793$ .

3. Hesabu kiasi cha mwisho

$A = 3570.79$

$3570.79$

$2, 657 \cdot 1.3439163793 = 3570.79$ .

$3570.79$

$2, 657 \cdot 1.3439163793 = 3570.79$ .

$3570.79$

$2, 657 \cdot 1.3439163793 = 3570.79$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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