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Ufumbuzi - Tiger algebra Suluhishaji

22675.33

22675.33

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2590, 15, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 590$ , $r = 15 %$ , $n = 2$ , $t = 15$ .

$c i (2590, 15, 2, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 590$ , $r = 15 %$ , $n = 2$ , $t = 15$ .

$P = 2590, r = 15 %, n = 2, t = 15$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 590$ , $r = 15 %$ , $n = 2$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 590$ , $r = 15 %$ , $n = 2$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 590$ , $r = 15 %$ , $n = 2$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.075$

$n t = 30$

${(1 + r / n)}^{(n t)}$

$r / n = 0.075, n t = 30, {(1 + r / n)}^{(n t)} = 8.754955189$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.075)}^{30} = 8.754955189$

$r / n = 0.075, n t = 30, {(1 + r / n)}^{(n t)} = 8.754955189$ .

$8.754955189$

$r / n = 0.075, n t = 30, {(1 + r / n)}^{(n t)} = 8.754955189$ .

3. Hesabu kiasi cha mwisho

$A = 22675.33$

$22675.33$

$2, 590 \cdot 8.754955189 = 22675.33$ .

$22675.33$

$2, 590 \cdot 8.754955189 = 22675.33$ .

$22675.33$

$2, 590 \cdot 8.754955189 = 22675.33$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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