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Ufumbuzi - Tiger algebra Suluhishaji

273143.24

273143.24

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24952, 13, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 952$ , $r = 13 %$ , $n = 2$ , $t = 19$ .

$c i (24952, 13, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 952$ , $r = 13 %$ , $n = 2$ , $t = 19$ .

$P = 24952, r = 13 %, n = 2, t = 19$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 952$ , $r = 13 %$ , $n = 2$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 952$ , $r = 13 %$ , $n = 2$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 952$ , $r = 13 %$ , $n = 2$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.065$

$n t = 38$

${(1 + r / n)}^{(n t)}$

$r / n = 0.065, n t = 38, {(1 + r / n)}^{(n t)} = 10.9467473682$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.065)}^{38} = 10.9467473682$

$r / n = 0.065, n t = 38, {(1 + r / n)}^{(n t)} = 10.9467473682$ .

$10.9467473682$

$r / n = 0.065, n t = 38, {(1 + r / n)}^{(n t)} = 10.9467473682$ .

3. Hesabu kiasi cha mwisho

$A = 273143.24$

$273143.24$

$24, 952 \cdot 10.9467473682 = 273143.24$ .

$273143.24$

$24, 952 \cdot 10.9467473682 = 273143.24$ .

$273143.24$

$24, 952 \cdot 10.9467473682 = 273143.24$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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