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Ufumbuzi - Tiger algebra Suluhishaji

40974.36

40974.36

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24914, 2, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 914$ , $r = 2 %$ , $n = 2$ , $t = 25$ .

$c i (24914, 2, 2, 25)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 914$ , $r = 2 %$ , $n = 2$ , $t = 25$ .

$P = 24914, r = 2 %, n = 2, t = 25$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 914$ , $r = 2 %$ , $n = 2$ , $t = 25$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 914$ , $r = 2 %$ , $n = 2$ , $t = 25$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 914$ , $r = 2 %$ , $n = 2$ , $t = 25$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 50$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 50, {(1 + r / n)}^{(n t)} = 1.6446318218$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{50} = 1.6446318218$

$r / n = 0.01, n t = 50, {(1 + r / n)}^{(n t)} = 1.6446318218$ .

$1.6446318218$

$r / n = 0.01, n t = 50, {(1 + r / n)}^{(n t)} = 1.6446318218$ .

3. Hesabu kiasi cha mwisho

$A = 40974.36$

$40974.36$

$24, 914 \cdot 1.6446318218 = 40974.36$ .

$40974.36$

$24, 914 \cdot 1.6446318218 = 40974.36$ .

$40974.36$

$24, 914 \cdot 1.6446318218 = 40974.36$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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