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Ufumbuzi - Tiger algebra Suluhishaji

27471.19

27471.19

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24858, 1, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 858$ , $r = 1 %$ , $n = 12$ , $t = 10$ .

$c i (24858, 1, 12, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 858$ , $r = 1 %$ , $n = 12$ , $t = 10$ .

$P = 24858, r = 1 %, n = 12, t = 10$

$\frac{1}{100} = 0.01$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 858$ , $r = 1 %$ , $n = 12$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 858$ , $r = 1 %$ , $n = 12$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 858$ , $r = 1 %$ , $n = 12$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0008333333$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0008333333, n t = 120, {(1 + r / n)}^{(n t)} = 1.1051248958$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0008333333)}^{120} = 1.1051248958$

$r / n = 0.0008333333, n t = 120, {(1 + r / n)}^{(n t)} = 1.1051248958$ .

$1.1051248958$

$r / n = 0.0008333333, n t = 120, {(1 + r / n)}^{(n t)} = 1.1051248958$ .

3. Hesabu kiasi cha mwisho

$A = 27471.19$

$27471.19$

$24, 858 \cdot 1.1051248958 = 27471.19$ .

$27471.19$

$24, 858 \cdot 1.1051248958 = 27471.19$ .

$27471.19$

$24, 858 \cdot 1.1051248958 = 27471.19$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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