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Ufumbuzi - Tiger algebra Suluhishaji

3474.30

3474.30

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2475, 2, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 475$ , $r = 2 %$ , $n = 4$ , $t = 17$ .

$c i (2475, 2, 4, 17)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 475$ , $r = 2 %$ , $n = 4$ , $t = 17$ .

$P = 2475, r = 2 %, n = 4, t = 17$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 475$ , $r = 2 %$ , $n = 4$ , $t = 17$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 475$ , $r = 2 %$ , $n = 4$ , $t = 17$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 475$ , $r = 2 %$ , $n = 4$ , $t = 17$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 68$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 68, {(1 + r / n)}^{(n t)} = 1.403757855$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{68} = 1.403757855$

$r / n = 0.005, n t = 68, {(1 + r / n)}^{(n t)} = 1.403757855$ .

$1.403757855$

$r / n = 0.005, n t = 68, {(1 + r / n)}^{(n t)} = 1.403757855$ .

3. Hesabu kiasi cha mwisho

$A = 3474.30$

$3474.30$

$2, 475 \cdot 1.403757855 = 3474.30$ .

$3474.30$

$2, 475 \cdot 1.403757855 = 3474.30$ .

$3474.30$

$2, 475 \cdot 1.403757855 = 3474.30$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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