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Ufumbuzi - Tiger algebra Suluhishaji

74387.39

74387.39

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24586, 6, 1, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 586$ , $r = 6 %$ , $n = 1$ , $t = 19$ .

$c i (24586, 6, 1, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 586$ , $r = 6 %$ , $n = 1$ , $t = 19$ .

$P = 24586, r = 6 %, n = 1, t = 19$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 586$ , $r = 6 %$ , $n = 1$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 586$ , $r = 6 %$ , $n = 1$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 586$ , $r = 6 %$ , $n = 1$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.06$

$n t = 19$

${(1 + r / n)}^{(n t)}$

$r / n = 0.06, n t = 19, {(1 + r / n)}^{(n t)} = 3.0255995021$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.06)}^{19} = 3.0255995021$

$r / n = 0.06, n t = 19, {(1 + r / n)}^{(n t)} = 3.0255995021$ .

$3.0255995021$

$r / n = 0.06, n t = 19, {(1 + r / n)}^{(n t)} = 3.0255995021$ .

3. Hesabu kiasi cha mwisho

$A = 74387.39$

$74387.39$

$24, 586 \cdot 3.0255995021 = 74387.39$ .

$74387.39$

$24, 586 \cdot 3.0255995021 = 74387.39$ .

$74387.39$

$24, 586 \cdot 3.0255995021 = 74387.39$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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