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Ufumbuzi - Tiger algebra Suluhishaji

414979.16

414979.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24432, 15, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 432$ , $r = 15 %$ , $n = 12$ , $t = 19$ .

$c i (24432, 15, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 432$ , $r = 15 %$ , $n = 12$ , $t = 19$ .

$P = 24432, r = 15 %, n = 12, t = 19$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 432$ , $r = 15 %$ , $n = 12$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 432$ , $r = 15 %$ , $n = 12$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 432$ , $r = 15 %$ , $n = 12$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 228$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 228, {(1 + r / n)}^{(n t)} = 16.9850672278$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{228} = 16.9850672278$

$r / n = 0.0125, n t = 228, {(1 + r / n)}^{(n t)} = 16.9850672278$ .

$16.9850672278$

$r / n = 0.0125, n t = 228, {(1 + r / n)}^{(n t)} = 16.9850672278$ .

3. Hesabu kiasi cha mwisho

$A = 414979.16$

$414979.16$

$24, 432 \cdot 16.9850672278 = 414979.16$ .

$414979.16$

$24, 432 \cdot 16.9850672278 = 414979.16$ .

$414979.16$

$24, 432 \cdot 16.9850672278 = 414979.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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