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Ufumbuzi - Tiger algebra Suluhishaji

351379.01

351379.01

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24332, 9, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 332$ , $r = 9 %$ , $n = 4$ , $t = 30$ .

$c i (24332, 9, 4, 30)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 332$ , $r = 9 %$ , $n = 4$ , $t = 30$ .

$P = 24332, r = 9 %, n = 4, t = 30$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 332$ , $r = 9 %$ , $n = 4$ , $t = 30$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 332$ , $r = 9 %$ , $n = 4$ , $t = 30$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 332$ , $r = 9 %$ , $n = 4$ , $t = 30$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0225$

$n t = 120$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0225, n t = 120, {(1 + r / n)}^{(n t)} = 14.4410243914$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0225)}^{120} = 14.4410243914$

$r / n = 0.0225, n t = 120, {(1 + r / n)}^{(n t)} = 14.4410243914$ .

$14.4410243914$

$r / n = 0.0225, n t = 120, {(1 + r / n)}^{(n t)} = 14.4410243914$ .

3. Hesabu kiasi cha mwisho

$A = 351379.01$

$351379.01$

$24, 332 \cdot 14.4410243914 = 351379.01$ .

$351379.01$

$24, 332 \cdot 14.4410243914 = 351379.01$ .

$351379.01$

$24, 332 \cdot 14.4410243914 = 351379.01$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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