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Ufumbuzi - Tiger algebra Suluhishaji

155230.95

155230.95

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24310, 10, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 310$ , $r = 10 %$ , $n = 2$ , $t = 19$ .

$c i (24310, 10, 2, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 310$ , $r = 10 %$ , $n = 2$ , $t = 19$ .

$P = 24310, r = 10 %, n = 2, t = 19$

$\frac{10}{100} = 0.1$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 310$ , $r = 10 %$ , $n = 2$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 310$ , $r = 10 %$ , $n = 2$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 310$ , $r = 10 %$ , $n = 2$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.05$

$n t = 38$

${(1 + r / n)}^{(n t)}$

$r / n = 0.05, n t = 38, {(1 + r / n)}^{(n t)} = 6.3854772899$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.05)}^{38} = 6.3854772899$

$r / n = 0.05, n t = 38, {(1 + r / n)}^{(n t)} = 6.3854772899$ .

$6.3854772899$

$r / n = 0.05, n t = 38, {(1 + r / n)}^{(n t)} = 6.3854772899$ .

3. Hesabu kiasi cha mwisho

$A = 155230.95$

$155230.95$

$24, 310 \cdot 6.3854772899 = 155230.95$ .

$155230.95$

$24, 310 \cdot 6.3854772899 = 155230.95$ .

$155230.95$

$24, 310 \cdot 6.3854772899 = 155230.95$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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