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Ufumbuzi - Tiger algebra Suluhishaji

12194.32

12194.32

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2423, 6, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 423$ , $r = 6 %$ , $n = 12$ , $t = 27$ .

$c i (2423, 6, 12, 27)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 423$ , $r = 6 %$ , $n = 12$ , $t = 27$ .

$P = 2423, r = 6 %, n = 12, t = 27$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 423$ , $r = 6 %$ , $n = 12$ , $t = 27$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 423$ , $r = 6 %$ , $n = 12$ , $t = 27$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 423$ , $r = 6 %$ , $n = 12$ , $t = 27$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.005$

$n t = 324$

${(1 + r / n)}^{(n t)}$

$r / n = 0.005, n t = 324, {(1 + r / n)}^{(n t)} = 5.0327343742$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.005)}^{324} = 5.0327343742$

$r / n = 0.005, n t = 324, {(1 + r / n)}^{(n t)} = 5.0327343742$ .

$5.0327343742$

$r / n = 0.005, n t = 324, {(1 + r / n)}^{(n t)} = 5.0327343742$ .

3. Hesabu kiasi cha mwisho

$A = 12194.32$

$12194.32$

$2, 423 \cdot 5.0327343742 = 12194.32$ .

$12194.32$

$2, 423 \cdot 5.0327343742 = 12194.32$ .

$12194.32$

$2, 423 \cdot 5.0327343742 = 12194.32$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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