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Ufumbuzi - Tiger algebra Suluhishaji

43720.53

43720.53

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24207, 6, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 207$ , $r = 6 %$ , $n = 2$ , $t = 10$ .

$c i (24207, 6, 2, 10)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 207$ , $r = 6 %$ , $n = 2$ , $t = 10$ .

$P = 24207, r = 6 %, n = 2, t = 10$

$\frac{6}{100} = 0.06$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 207$ , $r = 6 %$ , $n = 2$ , $t = 10$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 207$ , $r = 6 %$ , $n = 2$ , $t = 10$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 207$ , $r = 6 %$ , $n = 2$ , $t = 10$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.03$

$n t = 20$

${(1 + r / n)}^{(n t)}$

$r / n = 0.03, n t = 20, {(1 + r / n)}^{(n t)} = 1.8061112347$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.03)}^{20} = 1.8061112347$

$r / n = 0.03, n t = 20, {(1 + r / n)}^{(n t)} = 1.8061112347$ .

$1.8061112347$

$r / n = 0.03, n t = 20, {(1 + r / n)}^{(n t)} = 1.8061112347$ .

3. Hesabu kiasi cha mwisho

$A = 43720.53$

$43720.53$

$24, 207 \cdot 1.8061112347 = 43720.53$ .

$43720.53$

$24, 207 \cdot 1.8061112347 = 43720.53$ .

$43720.53$

$24, 207 \cdot 1.8061112347 = 43720.53$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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