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Ufumbuzi - Tiger algebra Suluhishaji

1215564.10

1215564.10

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (24017, 14, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 017$ , $r = 14 %$ , $n = 2$ , $t = 29$ .

$c i (24017, 14, 2, 29)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 017$ , $r = 14 %$ , $n = 2$ , $t = 29$ .

$P = 24017, r = 14 %, n = 2, t = 29$

$\frac{14}{100} = 0.14$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 017$ , $r = 14 %$ , $n = 2$ , $t = 29$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 017$ , $r = 14 %$ , $n = 2$ , $t = 29$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 24, 017$ , $r = 14 %$ , $n = 2$ , $t = 29$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 58$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 58, {(1 + r / n)}^{(n t)} = 50.6126533623$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{58} = 50.6126533623$

$r / n = 0.07, n t = 58, {(1 + r / n)}^{(n t)} = 50.6126533623$ .

$50.6126533623$

$r / n = 0.07, n t = 58, {(1 + r / n)}^{(n t)} = 50.6126533623$ .

3. Hesabu kiasi cha mwisho

$A = 1215564.10$

$1215564.10$

$24, 017 \cdot 50.6126533623 = 1215564.10$ .

$1215564.10$

$24, 017 \cdot 50.6126533623 = 1215564.10$ .

$1215564.10$

$24, 017 \cdot 50.6126533623 = 1215564.10$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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