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Ufumbuzi - Tiger algebra Suluhishaji

26738.65

26738.65

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23989, 11, 4, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 989$ , $r = 11 %$ , $n = 4$ , $t = 1$ .

$c i (23989, 11, 4, 1)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 989$ , $r = 11 %$ , $n = 4$ , $t = 1$ .

$P = 23989, r = 11 %, n = 4, t = 1$

$\frac{11}{100} = 0.11$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 989$ , $r = 11 %$ , $n = 4$ , $t = 1$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 989$ , $r = 11 %$ , $n = 4$ , $t = 1$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 989$ , $r = 11 %$ , $n = 4$ , $t = 1$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0275$

$n t = 4$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0275, n t = 4, {(1 + r / n)}^{(n t)} = 1.1146212594$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0275)}^{4} = 1.1146212594$

$r / n = 0.0275, n t = 4, {(1 + r / n)}^{(n t)} = 1.1146212594$ .

$1.1146212594$

$r / n = 0.0275, n t = 4, {(1 + r / n)}^{(n t)} = 1.1146212594$ .

3. Hesabu kiasi cha mwisho

$A = 26738.65$

$26738.65$

$23, 989 \cdot 1.1146212594 = 26738.65$ .

$26738.65$

$23, 989 \cdot 1.1146212594 = 26738.65$ .

$26738.65$

$23, 989 \cdot 1.1146212594 = 26738.65$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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