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Ufumbuzi - Tiger algebra Suluhishaji

41642.80

41642.80

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23853, 2, 2, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 853$ , $r = 2 %$ , $n = 2$ , $t = 28$ .

$c i (23853, 2, 2, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 853$ , $r = 2 %$ , $n = 2$ , $t = 28$ .

$P = 23853, r = 2 %, n = 2, t = 28$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 853$ , $r = 2 %$ , $n = 2$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 853$ , $r = 2 %$ , $n = 2$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 853$ , $r = 2 %$ , $n = 2$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 56$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 56, {(1 + r / n)}^{(n t)} = 1.7458098192$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{56} = 1.7458098192$

$r / n = 0.01, n t = 56, {(1 + r / n)}^{(n t)} = 1.7458098192$ .

$1.7458098192$

$r / n = 0.01, n t = 56, {(1 + r / n)}^{(n t)} = 1.7458098192$ .

3. Hesabu kiasi cha mwisho

$A = 41642.80$

$41642.80$

$23, 853 \cdot 1.7458098192 = 41642.80$ .

$41642.80$

$23, 853 \cdot 1.7458098192 = 41642.80$ .

$41642.80$

$23, 853 \cdot 1.7458098192 = 41642.80$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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