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Ufumbuzi - Tiger algebra Suluhishaji

569176.42

569176.42

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23831, 12, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 831$ , $r = 12 %$ , $n = 1$ , $t = 28$ .

$c i (23831, 12, 1, 28)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 831$ , $r = 12 %$ , $n = 1$ , $t = 28$ .

$P = 23831, r = 12 %, n = 1, t = 28$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 831$ , $r = 12 %$ , $n = 1$ , $t = 28$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 831$ , $r = 12 %$ , $n = 1$ , $t = 28$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 831$ , $r = 12 %$ , $n = 1$ , $t = 28$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.12$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.12, n t = 28, {(1 + r / n)}^{(n t)} = 23.8838664867$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.12)}^{28} = 23.8838664867$

$r / n = 0.12, n t = 28, {(1 + r / n)}^{(n t)} = 23.8838664867$ .

$23.8838664867$

$r / n = 0.12, n t = 28, {(1 + r / n)}^{(n t)} = 23.8838664867$ .

3. Hesabu kiasi cha mwisho

$A = 569176.42$

$569176.42$

$23, 831 \cdot 23.8838664867 = 569176.42$ .

$569176.42$

$23, 831 \cdot 23.8838664867 = 569176.42$ .

$569176.42$

$23, 831 \cdot 23.8838664867 = 569176.42$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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