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Ufumbuzi - Tiger algebra Suluhishaji

54104.79

54104.79

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23743, 4, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 743$ , $r = 4 %$ , $n = 1$ , $t = 21$ .

$c i (23743, 4, 1, 21)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 743$ , $r = 4 %$ , $n = 1$ , $t = 21$ .

$P = 23743, r = 4 %, n = 1, t = 21$

$\frac{4}{100} = 0.04$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 743$ , $r = 4 %$ , $n = 1$ , $t = 21$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 743$ , $r = 4 %$ , $n = 1$ , $t = 21$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 743$ , $r = 4 %$ , $n = 1$ , $t = 21$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.04$

$n t = 21$

${(1 + r / n)}^{(n t)}$

$r / n = 0.04, n t = 21, {(1 + r / n)}^{(n t)} = 2.2787680688$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.04)}^{21} = 2.2787680688$

$r / n = 0.04, n t = 21, {(1 + r / n)}^{(n t)} = 2.2787680688$ .

$2.2787680688$

$r / n = 0.04, n t = 21, {(1 + r / n)}^{(n t)} = 2.2787680688$ .

3. Hesabu kiasi cha mwisho

$A = 54104.79$

$54104.79$

$23, 743 \cdot 2.2787680688 = 54104.79$ .

$54104.79$

$23, 743 \cdot 2.2787680688 = 54104.79$ .

$54104.79$

$23, 743 \cdot 2.2787680688 = 54104.79$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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