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Ufumbuzi - Tiger algebra Suluhishaji

44048.01

44048.01

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23624, 9, 4, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 624$ , $r = 9 %$ , $n = 4$ , $t = 7$ .

$c i (23624, 9, 4, 7)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 624$ , $r = 9 %$ , $n = 4$ , $t = 7$ .

$P = 23624, r = 9 %, n = 4, t = 7$

$\frac{9}{100} = 0.09$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 624$ , $r = 9 %$ , $n = 4$ , $t = 7$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 624$ , $r = 9 %$ , $n = 4$ , $t = 7$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 624$ , $r = 9 %$ , $n = 4$ , $t = 7$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0225$

$n t = 28$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0225, n t = 28, {(1 + r / n)}^{(n t)} = 1.8645449901$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0225)}^{28} = 1.8645449901$

$r / n = 0.0225, n t = 28, {(1 + r / n)}^{(n t)} = 1.8645449901$ .

$1.8645449901$

$r / n = 0.0225, n t = 28, {(1 + r / n)}^{(n t)} = 1.8645449901$ .

3. Hesabu kiasi cha mwisho

$A = 44048.01$

$44048.01$

$23, 624 \cdot 1.8645449901 = 44048.01$ .

$44048.01$

$23, 624 \cdot 1.8645449901 = 44048.01$ .

$44048.01$

$23, 624 \cdot 1.8645449901 = 44048.01$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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