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Ufumbuzi - Tiger algebra Suluhishaji

32363.73

32363.73

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2340, 12, 12, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 340$ , $r = 12 %$ , $n = 12$ , $t = 22$ .

$c i (2340, 12, 12, 22)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 340$ , $r = 12 %$ , $n = 12$ , $t = 22$ .

$P = 2340, r = 12 %, n = 12, t = 22$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 340$ , $r = 12 %$ , $n = 12$ , $t = 22$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 340$ , $r = 12 %$ , $n = 12$ , $t = 22$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 340$ , $r = 12 %$ , $n = 12$ , $t = 22$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 264$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 264, {(1 + r / n)}^{(n t)} = 13.8306527853$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{264} = 13.8306527853$

$r / n = 0.01, n t = 264, {(1 + r / n)}^{(n t)} = 13.8306527853$ .

$13.8306527853$

$r / n = 0.01, n t = 264, {(1 + r / n)}^{(n t)} = 13.8306527853$ .

3. Hesabu kiasi cha mwisho

$A = 32363.73$

$32363.73$

$2, 340 \cdot 13.8306527853 = 32363.73$ .

$32363.73$

$2, 340 \cdot 13.8306527853 = 32363.73$ .

$32363.73$

$2, 340 \cdot 13.8306527853 = 32363.73$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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