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Ufumbuzi - Tiger algebra Suluhishaji

31509.98

31509.98

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23349, 2, 12, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 349$ , $r = 2 %$ , $n = 12$ , $t = 15$ .

$c i (23349, 2, 12, 15)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 349$ , $r = 2 %$ , $n = 12$ , $t = 15$ .

$P = 23349, r = 2 %, n = 12, t = 15$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 349$ , $r = 2 %$ , $n = 12$ , $t = 15$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 349$ , $r = 2 %$ , $n = 12$ , $t = 15$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 349$ , $r = 2 %$ , $n = 12$ , $t = 15$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0016666667$

$n t = 180$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0016666667, n t = 180, {(1 + r / n)}^{(n t)} = 1.3495217595$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0016666667)}^{180} = 1.3495217595$

$r / n = 0.0016666667, n t = 180, {(1 + r / n)}^{(n t)} = 1.3495217595$ .

$1.3495217595$

$r / n = 0.0016666667, n t = 180, {(1 + r / n)}^{(n t)} = 1.3495217595$ .

3. Hesabu kiasi cha mwisho

$A = 31509.98$

$31509.98$

$23, 349 \cdot 1.3495217595 = 31509.98$ .

$31509.98$

$23, 349 \cdot 1.3495217595 = 31509.98$ .

$31509.98$

$23, 349 \cdot 1.3495217595 = 31509.98$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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