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Ufumbuzi - Tiger algebra Suluhishaji

34123.65

34123.65

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2332, 15, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 332$ , $r = 15 %$ , $n = 12$ , $t = 18$ .

$c i (2332, 15, 12, 18)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 332$ , $r = 15 %$ , $n = 12$ , $t = 18$ .

$P = 2332, r = 15 %, n = 12, t = 18$

$\frac{15}{100} = 0.15$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 332$ , $r = 15 %$ , $n = 12$ , $t = 18$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 332$ , $r = 15 %$ , $n = 12$ , $t = 18$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 332$ , $r = 15 %$ , $n = 12$ , $t = 18$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0125$

$n t = 216$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0125, n t = 216, {(1 + r / n)}^{(n t)} = 14.6327814955$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0125)}^{216} = 14.6327814955$

$r / n = 0.0125, n t = 216, {(1 + r / n)}^{(n t)} = 14.6327814955$ .

$14.6327814955$

$r / n = 0.0125, n t = 216, {(1 + r / n)}^{(n t)} = 14.6327814955$ .

3. Hesabu kiasi cha mwisho

$A = 34123.65$

$34123.65$

$2, 332 \cdot 14.6327814955 = 34123.65$ .

$34123.65$

$2, 332 \cdot 14.6327814955 = 34123.65$ .

$34123.65$

$2, 332 \cdot 14.6327814955 = 34123.65$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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