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Ufumbuzi - Tiger algebra Suluhishaji

70021.21

70021.21

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23309, 13, 1, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 309$ , $r = 13 %$ , $n = 1$ , $t = 9$ .

$c i (23309, 13, 1, 9)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 309$ , $r = 13 %$ , $n = 1$ , $t = 9$ .

$P = 23309, r = 13 %, n = 1, t = 9$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 309$ , $r = 13 %$ , $n = 1$ , $t = 9$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 309$ , $r = 13 %$ , $n = 1$ , $t = 9$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 309$ , $r = 13 %$ , $n = 1$ , $t = 9$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.13$

$n t = 9$

${(1 + r / n)}^{(n t)}$

$r / n = 0.13, n t = 9, {(1 + r / n)}^{(n t)} = 3.004041938$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.13)}^{9} = 3.004041938$

$r / n = 0.13, n t = 9, {(1 + r / n)}^{(n t)} = 3.004041938$ .

$3.004041938$

$r / n = 0.13, n t = 9, {(1 + r / n)}^{(n t)} = 3.004041938$ .

3. Hesabu kiasi cha mwisho

$A = 70021.21$

$70021.21$

$23, 309 \cdot 3.004041938 = 70021.21$ .

$70021.21$

$23, 309 \cdot 3.004041938 = 70021.21$ .

$70021.21$

$23, 309 \cdot 3.004041938 = 70021.21$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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