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Ufumbuzi - Tiger algebra Suluhishaji

39738.02

39738.02

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23234, 5, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 234$ , $r = 5 %$ , $n = 1$ , $t = 11$ .

$c i (23234, 5, 1, 11)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 234$ , $r = 5 %$ , $n = 1$ , $t = 11$ .

$P = 23234, r = 5 %, n = 1, t = 11$

$\frac{5}{100} = 0.05$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 234$ , $r = 5 %$ , $n = 1$ , $t = 11$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 234$ , $r = 5 %$ , $n = 1$ , $t = 11$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 234$ , $r = 5 %$ , $n = 1$ , $t = 11$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.05$

$n t = 11$

${(1 + r / n)}^{(n t)}$

$r / n = 0.05, n t = 11, {(1 + r / n)}^{(n t)} = 1.7103393581$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.05)}^{11} = 1.7103393581$

$r / n = 0.05, n t = 11, {(1 + r / n)}^{(n t)} = 1.7103393581$ .

$1.7103393581$

$r / n = 0.05, n t = 11, {(1 + r / n)}^{(n t)} = 1.7103393581$ .

3. Hesabu kiasi cha mwisho

$A = 39738.02$

$39738.02$

$23, 234 \cdot 1.7103393581 = 39738.02$ .

$39738.02$

$23, 234 \cdot 1.7103393581 = 39738.02$ .

$39738.02$

$23, 234 \cdot 1.7103393581 = 39738.02$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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