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Ufumbuzi - Tiger algebra Suluhishaji

223636.52

223636.52

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23135, 12, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 135$ , $r = 12 %$ , $n = 12$ , $t = 19$ .

$c i (23135, 12, 12, 19)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 135$ , $r = 12 %$ , $n = 12$ , $t = 19$ .

$P = 23135, r = 12 %, n = 12, t = 19$

$\frac{12}{100} = 0.12$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 135$ , $r = 12 %$ , $n = 12$ , $t = 19$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 135$ , $r = 12 %$ , $n = 12$ , $t = 19$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 135$ , $r = 12 %$ , $n = 12$ , $t = 19$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 228$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 228, {(1 + r / n)}^{(n t)} = 9.6665883013$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{228} = 9.6665883013$

$r / n = 0.01, n t = 228, {(1 + r / n)}^{(n t)} = 9.6665883013$ .

$9.6665883013$

$r / n = 0.01, n t = 228, {(1 + r / n)}^{(n t)} = 9.6665883013$ .

3. Hesabu kiasi cha mwisho

$A = 223636.52$

$223636.52$

$23, 135 \cdot 9.6665883013 = 223636.52$ .

$223636.52$

$23, 135 \cdot 9.6665883013 = 223636.52$ .

$223636.52$

$23, 135 \cdot 9.6665883013 = 223636.52$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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