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Ufumbuzi - Tiger algebra Suluhishaji

64295.16

64295.16

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2310, 13, 4, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 310$ , $r = 13 %$ , $n = 4$ , $t = 26$ .

$c i (2310, 13, 4, 26)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 310$ , $r = 13 %$ , $n = 4$ , $t = 26$ .

$P = 2310, r = 13 %, n = 4, t = 26$

$\frac{13}{100} = 0.13$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 310$ , $r = 13 %$ , $n = 4$ , $t = 26$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 310$ , $r = 13 %$ , $n = 4$ , $t = 26$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 310$ , $r = 13 %$ , $n = 4$ , $t = 26$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.0325$

$n t = 104$

${(1 + r / n)}^{(n t)}$

$r / n = 0.0325, n t = 104, {(1 + r / n)}^{(n t)} = 27.833400844$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.0325)}^{104} = 27.833400844$

$r / n = 0.0325, n t = 104, {(1 + r / n)}^{(n t)} = 27.833400844$ .

$27.833400844$

$r / n = 0.0325, n t = 104, {(1 + r / n)}^{(n t)} = 27.833400844$ .

3. Hesabu kiasi cha mwisho

$A = 64295.16$

$64295.16$

$2, 310 \cdot 27.833400844 = 64295.16$ .

$64295.16$

$2, 310 \cdot 27.833400844 = 64295.16$ .

$64295.16$

$2, 310 \cdot 27.833400844 = 64295.16$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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