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Ufumbuzi - Tiger algebra Suluhishaji

25931.62

25931.62

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (23013, 2, 2, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 013$ , $r = 2 %$ , $n = 2$ , $t = 6$ .

$c i (23013, 2, 2, 6)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 013$ , $r = 2 %$ , $n = 2$ , $t = 6$ .

$P = 23013, r = 2 %, n = 2, t = 6$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 013$ , $r = 2 %$ , $n = 2$ , $t = 6$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 013$ , $r = 2 %$ , $n = 2$ , $t = 6$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 23, 013$ , $r = 2 %$ , $n = 2$ , $t = 6$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 12$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 12, {(1 + r / n)}^{(n t)} = 1.1268250301$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{12} = 1.1268250301$

$r / n = 0.01, n t = 12, {(1 + r / n)}^{(n t)} = 1.1268250301$ .

$1.1268250301$

$r / n = 0.01, n t = 12, {(1 + r / n)}^{(n t)} = 1.1268250301$ .

3. Hesabu kiasi cha mwisho

$A = 25931.62$

$25931.62$

$23, 013 \cdot 1.1268250301 = 25931.62$ .

$25931.62$

$23, 013 \cdot 1.1268250301 = 25931.62$ .

$25931.62$

$23, 013 \cdot 1.1268250301 = 25931.62$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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