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Ufumbuzi - Tiger algebra Suluhishaji

2976.82

2976.82

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (2271, 7, 1, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 271$ , $r = 7 %$ , $n = 1$ , $t = 4$ .

$c i (2271, 7, 1, 4)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 271$ , $r = 7 %$ , $n = 1$ , $t = 4$ .

$P = 2271, r = 7 %, n = 1, t = 4$

$\frac{7}{100} = 0.07$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 271$ , $r = 7 %$ , $n = 1$ , $t = 4$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 271$ , $r = 7 %$ , $n = 1$ , $t = 4$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 2, 271$ , $r = 7 %$ , $n = 1$ , $t = 4$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.07$

$n t = 4$

${(1 + r / n)}^{(n t)}$

$r / n = 0.07, n t = 4, {(1 + r / n)}^{(n t)} = 1.31079601$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.07)}^{4} = 1.31079601$

$r / n = 0.07, n t = 4, {(1 + r / n)}^{(n t)} = 1.31079601$ .

$1.31079601$

$r / n = 0.07, n t = 4, {(1 + r / n)}^{(n t)} = 1.31079601$ .

3. Hesabu kiasi cha mwisho

$A = 2976.82$

$2976.82$

$2, 271 \cdot 1.31079601 = 2976.82$ .

$2976.82$

$2, 271 \cdot 1.31079601 = 2976.82$ .

$2976.82$

$2, 271 \cdot 1.31079601 = 2976.82$ .

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

Vigezo na mada

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