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Ufumbuzi - Tiger algebra Suluhishaji

29393.25

29393.25

Tazama hatua Jifunze zaidi na Tiger Jaribu hili:

Maelezo kwa hatua

1. Weka fomula ya riba changamano

$c i (22693, 2, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 693$ , $r = 2 %$ , $n = 2$ , $t = 13$ .

$c i (22693, 2, 2, 13)$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 693$ , $r = 2 %$ , $n = 2$ , $t = 13$ .

$P = 22693, r = 2 %, n = 2, t = 13$

$\frac{2}{100} = 0.02$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 693$ , $r = 2 %$ , $n = 2$ , $t = 13$ .

$A = P {(1 + r / n)}^{(n t)}$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 693$ , $r = 2 %$ , $n = 2$ , $t = 13$ .

$N e x t c o m p u t e r / n, n t, a n d {(1 + r / n)}^{(n t)} .$

Tumia fomula $A = P {(1 + r / n)}^{(n t)}$ ukiwa na $P = 22, 693$ , $r = 2 %$ , $n = 2$ , $t = 13$ .

2. Hesabu kipengele cha ukuaji

$\frac{r}{n} = 0.01$

$n t = 26$

${(1 + r / n)}^{(n t)}$

$r / n = 0.01, n t = 26, {(1 + r / n)}^{(n t)} = 1.295256315$ .

${(1 + r / n)}^{(n t)}$

${(1 + 0.01)}^{26} = 1.295256315$

$r / n = 0.01, n t = 26, {(1 + r / n)}^{(n t)} = 1.295256315$ .

$1.295256315$

$r / n = 0.01, n t = 26, {(1 + r / n)}^{(n t)} = 1.295256315$ .

3. Hesabu kiasi cha mwisho

$A = 29393.25$

$29393.25$

$22, 693 \cdot 1.295256315 = 29393.25$ .

$29393.25$

$22, 693 \cdot 1.295256315 = 29393.25$ .

$29393.25$

$22, 693 \cdot 1.295256315 = 29393.25$ .

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Jifunze zaidi na Tiger

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Tiger algebra Suluhishaji

Ufumbuzi - Tiger algebra Suluhishaji

Maelezo kwa hatua

1. Weka fomula ya riba changamano

2. Hesabu kipengele cha ukuaji

3. Hesabu kiasi cha mwisho

Kwa nini kujifunza hii

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